HCF and LCM— Concepts, Formulas & Shortcuts
- HCF × LCM = product of the two numbers (true for exactly two numbers).
- "Greatest number that divides x, y, z" → HCF. "Least number divisible by x, y, z" → LCM.
- Least number leaving remainder r with each divisor = LCM + r.
- Greatest number leaving the SAME remainder = HCF of the differences of the numbers.
- If numbers are in ratio a : b with HCF h, the numbers are ah and bh and the LCM is abh.
- HCF of fractions = HCF(numerators)/LCM(denominators); LCM of fractions = LCM(numerators)/HCF(denominators).
HCF and LCM Practice Questions with Answers
Attempt each question first, then open the explanation. All 24 questions below are free to read and require no signup.
Q1.The HCF of 24 and 36 is:
Easy- A6
- B8
- C12
- D18
HCF and LCM question 1 of 24+Show Answer & Explanation
Answer: C. 12
Explanation: 24 = 2³ × 3, 36 = 2² × 3² → common = 2² × 3 = 12.
Q2.The LCM of 12, 15 and 20 is:
Easy- A30
- B48
- C60
- D120
HCF and LCM question 2 of 24+Show Answer & Explanation
Answer: C. 60
Explanation: 12 = 2²·3, 15 = 3·5, 20 = 2²·5 → LCM = 2² × 3 × 5 = 60.
Q3.The product of two numbers is 2,028 and their HCF is 13. Their LCM is:
Easy- A26
- B78
- C156
- D169
HCF and LCM question 3 of 24+Show Answer & Explanation
Answer: C. 156
Explanation: LCM = product/HCF = 2028/13 = 156.
Q4.The greatest number that divides 43, 91 and 183 leaving the same remainder in each case is:
Difficult- A4
- B7
- C9
- D13
HCF and LCM question 4 of 24+Show Answer & Explanation
Answer: A. 4
Explanation: Differences: 91 − 43 = 48, 183 − 91 = 92, 183 − 43 = 140. HCF(48, 92, 140) = 4.
Q5.The least number which when divided by 6, 7 and 8 leaves a remainder 3 in each case is:
Moderate- A165
- B168
- C171
- D175
HCF and LCM question 5 of 24+Show Answer & Explanation
Answer: C. 171
Explanation: LCM(6,7,8) = 168 → required number = 168 + 3 = 171.
Q6.The HCF of two numbers is 11 and their LCM is 7,700. If one number is 275, the other is:
Moderate- A288
- B308
- C318
- D330
HCF and LCM question 6 of 24+Show Answer & Explanation
Answer: B. 308
Explanation: Other = (11 × 7700)/275 = 84700/275 = 308.
Q7.The smallest number exactly divisible by 12, 16, 18 and 21 is:
Moderate- A504
- B1,008
- C1,512
- D2,016
HCF and LCM question 7 of 24+Show Answer & Explanation
Answer: B. 1,008
Explanation: LCM = 2⁴ × 3² × 7 = 1,008.
Q8.Two numbers are in the ratio 3 : 4 and their HCF is 4. Their LCM is:
Moderate- A24
- B36
- C48
- D96
HCF and LCM question 8 of 24+Show Answer & Explanation
Answer: C. 48
Explanation: The numbers are 12 and 16 → LCM = 48 (equivalently 3 × 4 × 4).
Q9.The HCF of 18 and 30 is:
Easy- A3
- B6
- C9
- D15
HCF and LCM question 9 of 24+Show Answer & Explanation
Answer: B. 6
Explanation: 18 = 2 × 3², 30 = 2 × 3 × 5 → common = 2 × 3 = 6.
Q10.The LCM of 8 and 12 is:
Easy- A16
- B24
- C36
- D48
HCF and LCM question 10 of 24+Show Answer & Explanation
Answer: B. 24
Explanation: 8 = 2³, 12 = 2² × 3 → LCM = 2³ × 3 = 24.
Q11.The HCF of two co-prime numbers is always:
Easy- A0
- B1
- Ctheir product
- Dthe smaller number
HCF and LCM question 11 of 24+Show Answer & Explanation
Answer: B. 1
Explanation: Co-prime numbers share no common factor other than 1.
Q12.The greatest number that divides 60, 84 and 108 exactly is:
Moderate- A6
- B12
- C18
- D24
HCF and LCM question 12 of 24+Show Answer & Explanation
Answer: B. 12
Explanation: HCF(60, 84, 108) = 12.
Q13.The least number which when divided by 5, 6 and 8 leaves a remainder 2 is:
Moderate- A118
- B120
- C122
- D125
HCF and LCM question 13 of 24+Show Answer & Explanation
Answer: C. 122
Explanation: LCM(5, 6, 8) = 120 → required number = 120 + 2 = 122.
Q14.Three bells ring at intervals of 6, 8 and 12 minutes. If they ring together at 9:00 am, they will next ring together at:
Moderate- A9:12 am
- B9:24 am
- C9:36 am
- D9:48 am
HCF and LCM question 14 of 24+Show Answer & Explanation
Answer: B. 9:24 am
Explanation: LCM(6, 8, 12) = 24 minutes → they next coincide at 9:24 am.
Q15.The LCM of two numbers is 48 and their HCF is 4. If one number is 12, the other is:
Moderate- A8
- B12
- C16
- D24
HCF and LCM question 15 of 24+Show Answer & Explanation
Answer: C. 16
Explanation: Product = HCF × LCM = 4 × 48 = 192 → other = 192/12 = 16.
Q16.The HCF of 1/2, 3/4 and 5/6 is:
Difficult- A1/2
- B1/12
- C1/6
- D5/12
HCF and LCM question 16 of 24+Show Answer & Explanation
Answer: B. 1/12
Explanation: HCF of fractions = HCF(numerators)/LCM(denominators) = HCF(1,3,5)/LCM(2,4,6) = 1/12.
Q17.The HCF of 12 and 20 is:
Easy- A2
- B4
- C6
- D10
HCF and LCM question 17 of 24+Show Answer & Explanation
Answer: B. 4
Explanation: 12 = 2²·3, 20 = 2²·5 → HCF = 4.
Q18.The LCM of 6 and 10 is:
Easy- A16
- B20
- C30
- D60
HCF and LCM question 18 of 24+Show Answer & Explanation
Answer: C. 30
Explanation: 6 = 2·3, 10 = 2·5 → LCM = 2 × 3 × 5 = 30.
Q19.The HCF of 15, 25 and 35 is:
Easy- A3
- B5
- C7
- D15
HCF and LCM question 19 of 24+Show Answer & Explanation
Answer: B. 5
Explanation: All three share only the factor 5.
Q20.The LCM of 4, 6 and 10 is:
Moderate- A30
- B40
- C60
- D120
HCF and LCM question 20 of 24+Show Answer & Explanation
Answer: C. 60
Explanation: LCM = 2² × 3 × 5 = 60.
Q21.The greatest number that divides 90 and 126 exactly is:
Moderate- A6
- B12
- C18
- D24
HCF and LCM question 21 of 24+Show Answer & Explanation
Answer: C. 18
Explanation: 90 = 2·3²·5 and 126 = 2·3²·7 → HCF = 2 × 9 = 18.
Q22.Two numbers have HCF 6 and LCM 36. If one number is 12, the other is:
Moderate- A12
- B18
- C24
- D36
HCF and LCM question 22 of 24+Show Answer & Explanation
Answer: B. 18
Explanation: Product = 6 × 36 = 216 → other = 216/12 = 18.
Q23.The smallest number divisible by 8, 10 and 12 is:
Moderate- A80
- B100
- C120
- D240
HCF and LCM question 23 of 24+Show Answer & Explanation
Answer: C. 120
Explanation: LCM(8, 10, 12) = 120.
Q24.Two bells ring every 15 and 20 minutes. If they ring together at noon, they next ring together at:
Moderate- A12:30
- B12:45
- C1:00
- D1:15
HCF and LCM question 24 of 24+Show Answer & Explanation
Answer: C. 1:00
Explanation: LCM(15, 20) = 60 minutes → they coincide again at 1:00.
HCF and LCM — Frequently Asked Questions
How do I find the greatest number that leaves the same remainder?+
Take the pairwise differences of the given numbers and find their HCF. For 43, 91 and 183 the differences are 48, 92 and 140, whose HCF is 4.
Does HCF × LCM = product work for three numbers?+
No. It holds only for two numbers. For three or more, compute the HCF and LCM separately by prime factorisation.
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